Passing a pointer to an array of an array

[Munchor]

I need some help with a pointer problem I'm facing. I have this:

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int my_array[26][24]; /* An 2 dimensions array */ call_function(NEED_HELP_HERE);

call_function() requires an argument, an array. I need to pass my_array. However, I know that passing arrays in functions is memory consuming and not very clean. So, instead, I want to pass a pointer to the array.

So my question is how to declare the pointer to the array, how do I declare it?

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void call_function(NEED_HELP_HERE) {   /* This function receives a pointer to an array as argument */ }

The question is what to put in "NEED_HELP_HERE" places. My issue is that I don't know what type the pointer to the array of arrays is.

Thanks in advance!

[thepenguin77]

That might work, but why not save all the hassle and do this?

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int my_array[26][24] = {0}; call_function(my_array); //////////////////////////////// void call_function(int array[26][24]) { for (int iii = 0; iii<26; iii++) { for (int jjj = 0; jjj<24; jjj++) { array[iii][jjj] = iii*jjj; } } }

When you just type the name of an array, like "my_array," that actually is the pointer to the array. You only dereference it when you start to use [].

Also, I would suggest that you use a 1 dimensional array. Two dimensional arrays are just handled like 1 dimensional arrays in memory anyways.

[Munchor]

That might work, but why not save all the hassle and do this?

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int my_array[26][24] = {0}; call_function(my_array); //////////////////////////////// void call_function(int array[26][24]) {   for (int iii = 0; iii<26; iii++)   {     for (int jjj = 0; jjj<24; jjj++)     {        array[iii][jjj] = iii*jjj;     }   } }

When you just type the name of an array, like "my_array," that actually is the pointer to the array. You only dereference it when you start to use [].

Also, I would suggest that you use a 1 dimensional array. Two dimensional arrays are just handled like 1 dimensional arrays in memory anyways.

Oh ooops, I forgot arrays are just pointers, how silly of me, thanks for reminding me