Grammer Tutorial

[Yeong]

since juju's server works now, this is an alternate address:
http://www.yeong.57o9.org

[Yeong]

Chapter 4 added. I decided to separate Loops and Logic since the page was getting big X.x

[Xeda112358]

Hmm, AND and OR (and even XOR) are math operations... So what they really do is perform Bit-Wise logic. For example, if you do "3 and 6", it will return 2. The reason is if you AND these two:
0000000000000011 (this is 3 in binary)
0000000000000110 (this is 6 in binary)
0000000000000010 (you get this which is 2)

The result has a 1 bit only if both bits from the inputs are 1. So, if you did this:

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1 2	If A=3: and B=6

You would be doing this:

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1 2	If (A=3) and (B=6)

However, doing this will result in 0 no matter what:

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1 2	If A=6 and B=3

Lets say B=3 and A=6. The reason is that if you break it down:
A=6 and B=3
A=6 and 1
A=0
0

See the issue? 6 and 1 returns 0

[Yeong]

Ok, xeda. I'll try to implement that.
Ch 5 coming out tomorrow.

[Xeda112358]

I still see:

Conditon1 AND Conditon2: Returns "true" only if two conditons are true.
Conditon1 OR Condition2 : Returns "true" as long as at least one of the conditions is true.

Those aren't correct

[Yeong]

Oh. I have it fixed. I just haven't uploaded yet.
I think I'll upload them all at once once I reach like ch.10.

[Xeda112358]

Ah, okay Can't wait When I update the command list, I am probably going to link to your tutorial

[Yeong]

oh wait. I just correctly understood your bitwise logic. XP
Time to fix it again.
Also, Grammer does have XOR, right?

[Xeda112358]

Yes, it is the xor token

[Yeong]

now that means that I have to add XOR command.... XP