Message #241366

[jacobly]

"Pic0" is actually 3 bytes long (not including the terminating 0).

Since the first two bytes are always the same, you could do:

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"Pic0Pic1Pic2Pic3Pic4Pic5Pic6Pic7Pic8Pic9"→Z "Pic1"→I GetCalc("varP")→Q float{Q}→P {P*3+Z+2}→{I+2}

But an even better method would be:

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"Pic1"→I GetCalc("varP")→Q float{Q}→P (P?-1,9)→{I+2} .Pic1-Pic9 is 0-8, and Pic0 is 9.

Edit: Not enough parentheses. Also, that's subtract 1, not negative 1.