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Author Topic: Axe Q&A -  (Read 59337 times) Bookmark and Share
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Darl181
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« Reply #1290 on: 08 January, 2012, 08:07:27 »
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No, Text() can only write to L6.  It's hard-coded into the routine.
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« Reply #1291 on: 08 January, 2012, 08:09:23 »
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Quote from: Darl181 on 08 January, 2012, 08:07:27
No, Text() can only write to L6.  It's hard-coded into the routine.
Dang. I'll have to do some tricky buffer copying. Smiley
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« Reply #1292 on: 08 January, 2012, 10:34:17 »
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Blame TI for that.  If you want to draw directly to the back-buffer, you'd have to make your own font routine, which is easy, but takes forever to get all those letter/number/symbol sprites as well as a lot of space in the program itself.  But sometimes a kick-ass font can really improve a game's look! Cheesy
« Last Edit: 08 January, 2012, 10:34:40 by Quigibo » Logged
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« Reply #1293 on: 08 January, 2012, 22:19:15 »
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With Z-Select, does it Goto the label or does it run it as a subroutine?
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« Reply #1294 on: 09 January, 2012, 02:44:45 »
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Quote from: jacobly on 07 January, 2012, 17:24:50
Quote from: Builderboy on 07 January, 2012, 05:57:20
I know the result can be determined by some sort of binary combination of the two numbers but I can't remember which.
(A or B) xor 3 or equivalently 3-(A or B)
Wait so even if both calculators input the same number to Port (0 and 0 say), they would each read the inverse of that number (3) ?  That's weird Big frown

Quote from: Darl181 on 08 January, 2012, 22:19:15
With Z-Select, does it Goto the label or does it run it as a subroutine?
It Goto's the Label
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« Reply #1295 on: 09 January, 2012, 05:29:55 »
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That sounds useful!
what do you mean the inverse?
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« Reply #1296 on: 09 January, 2012, 05:45:29 »
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Binary inverse, as in all the bits get flipped.  The result read depends on how Axe treats the output of the Port, as well as how the Ports interact.  I was under the impression there was some sort of logical equation, but I also thought that if both calcs agreed on an output number, the input read would be equal to that number.
« Last Edit: 09 January, 2012, 05:46:35 by Builderboy » Logged
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« Reply #1297 on: 10 January, 2012, 03:09:55 »
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Do you have to do something special to write to a GDB?
I tried using this one line in my code and I got an ERR:UNDEFINED

Copy(L1,GDB1,768)
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« Reply #1298 on: 10 January, 2012, 03:45:32 »
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You don't need to do anything special (unless you are writing an app, in which case it won't work) but you need to have GDB1 defined already.  Do you?
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« Reply #1299 on: 10 January, 2012, 03:49:32 »
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I thought L1 was smaller than 768 bytes?
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« Reply #1300 on: 10 January, 2012, 03:50:31 »
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L1 is 714 bytes says the axe commands list.
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« Reply #1301 on: 10 January, 2012, 04:07:30 »
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Quote from: TBO_Yeong on 10 January, 2012, 03:49:32
I thought L1 was smaller than 768 bytes?
If you first Realloc the variables it makes L1 768 bytes.  Perhaps he did that.
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« Reply #1302 on: 10 January, 2012, 05:12:33 »
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Quote from: parser padwan on 08 January, 2012, 08:09:23
Quote from: Darl181 on 08 January, 2012, 08:07:27
No, Text() can only write to L6.  It's hard-coded into the routine.
Dang. I'll have to do some tricky buffer copying. Smiley

DispGraph(L3, L6)r should work unless Axe doesn't allow the buffers to be switched
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« Reply #1303 on: 10 January, 2012, 05:14:38 »
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That should work.
The only other way I can think of is to have l6 blank, write the text, and copy the buffer to L3 or something.
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« Reply #1304 on: 10 January, 2012, 05:34:05 »
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Quote from: Builderboy on 10 January, 2012, 03:45:32
You don't need to do anything special (unless you are writing an app, in which case it won't work) but you need to have GDB1 defined already.  Do you?
I don't think so, what do I have to do to make it defined?
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