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Cadan v2 - Progress Thread

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Geekboy1011:
Ok here we go. This is the new thread for progress on Cadan v2

Current Revision:v0.004a
Stable Download:N/A
Beta Download:N/A
Repository:https://bitbucket.org/CFD_LLC/cadan

Progress Summary:
Pre-2013-03-28 The year or so up to this point Cadan got its internal overhaul and was brought up to the 3 page app it is now.
2013-03-29 Cadan Got a repo on bitbuket managed by geekboy
2013-04-01 Debugging toggles added to make our lifes easier.
2013-04-01 Rearanged the player files for my sanity
2013-04-07 Got a completily new playershot handler mych saner and easier to work with
2013-04-08 Started importing player routines. New setup is nice :D
2013-12-14 Started working on this again. Another restructure. Might actually move some where this time



This title post will only be edited with major updates from here on out. The information at the top will always be to the latest available versions.
Want to help ask! want to comment and say its awesome go for it! want to lurk and be boring NO CHERRIES FOR YOU >:F

Link:
Well, for Iambian's arrival stuff like slowing down; I found these for the project:

http://www.red3d.com/cwr/steer/
http://www.red3d.com/cwr/steer/Arrival.html
http://www.red3d.com/cwr/steer/gdc99/

Iambian:
Post indicating my appoval of this thread or something like that. Not entirely sure but I was asked to post something.


Right. Edit: Need info on fast algorithm for finding distance of a line given two coordinate pairs x,y

EDIT: Modification to this post has absolutely nothing to do with the topic. In fact, I was just looking for an old post that no one (should) notice to slip this file in as an attachment. Because other file hosting services suck. Shh... (NOTE: This file is source for an interrupt-based audio driver)

calc84maniac:

--- Quote from: Iambian on April 30, 2013, 11:41:23 pm ---Edit: Need info on fast algorithm for finding distance of a line given two coordinate pairs x,y

--- End quote ---

What's the range of x,y? 0-63?

Geekboy1011:
I believe so Calc.  Assume yes I'll text him later to confirm 

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