Author Topic: 8 Balls  (Read 1548 times)

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Offline Happybobjr

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8 Balls
« on: November 27, 2012, 08:02:17 pm »
Ok, after seeing Builder's awesome riddle, which I solved (ok, not really), I figured I could be nice and make you think of two at once. >:D.


You have 8 identical Blue Lobsters and one balance. Lets say it looks like this.


One of the lobster's weighs slightly more than the rest, but you can't tell by holding it or anything.  You are overcome with the sudden urge to know which one is the one that weighs more.  Warning though, you have only time enough to use the balance twice before Netham attacks you with a Banana Razor!  How can you tell which is the heavier?

Spoiler For In other words:
1) 8 lobsters. 7 weigh same. 1 weighs tiniest bit more.
2) 1 balance
3) You can only use the balance twice
4) Find the heavier lobster


Same rules apply to mine as his. There is no trickery.
You can't just say 'Oh! this one feels like it might weigh more.
Good luck.
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Offline dinosteven

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Re: 8 Balls
« Reply #1 on: November 27, 2012, 09:40:22 pm »
Spoiler For My Answer:
Weigh 3 lobsters against 3 lobsters.

a: If they're the same: Weigh the remaining 2 lobsters and the heavier lobster is the one you want to find.

b: If they're different: Take the 3 lobsters on the heavy side. Measure 1 lobster against another.
b1: If they're different: The heavier lobster is the correct one.
b2: If they're the same: The 3rd lobster not weighed is the correct one.

Offline Happybobjr

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Re: 8 Balls
« Reply #2 on: November 27, 2012, 10:19:20 pm »
yup

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Offline dinosteven

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Re: 8 Balls
« Reply #3 on: November 27, 2012, 11:06:41 pm »
Yay! This is the 1st brainteaser I've been able to solve.

Offline Scipi

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Re: 8 Balls
« Reply #4 on: November 27, 2012, 11:12:22 pm »
My answer:

Spoiler For Spoiler:
Divide into two groups of three and one of two

Weigh the two groups of three against eachother and of one is heavier, measure two out of the three. If one is heavier than the other, that' the one, else it's the third one you didn't weigh.

If both groups of three weigh the same, weigh the remaining two and whichever is heavier is it.

Probably the same as the correct answer :P I've seen questions like this before.

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Spoiler For IMPORTANT NEWS!:
Late last night, Quebec was invaded by a group calling themselves, "Omnimaga". Not much is known about these mysterious people except that they all carried calculators of some kind and they all seemed to converge on one house in particular. Experts estimate that the combined power of their fabled calculators is greater than all the worlds super computers put together. The group seems to be holding out in the home of a certain DJ_O, who the Omnimagians claim to be their founder. Such power has put the world at a standstill with everyone waiting to see what the Omnimagians will do...

Wait... This just in, the Omnimagians have sent the UN a list of demands that must be met or else the world will be "submitted to the wrath of Netham45's Lobster Army". Such demands include >9001 crates of peanuts, sacrificial blue lobsters, and a wide assortment of cherry flavored items. With such computing power stored in the hands of such people, we can only hope these demands are met.

In the wake of these events, we can only ask, Why? Why do these people make these demands, what caused them to gather, and what are their future plans...