Author Topic: calculating the natural logarithm of an arbitrary number  (Read 2230 times)

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Offline aeTIos

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calculating the natural logarithm of an arbitrary number
« on: December 23, 2011, 09:09:29 am »
Hello guys,

As stated in the subject. I can't use this: since that only works for x=-1 through x=1...

Who knows another summation/computation algorithm? Thanks!
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Offline bsl

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Re: calculating the natural logarithm of an arbitrary number
« Reply #1 on: December 23, 2011, 09:52:03 am »
Hello guys,

As stated in the subject. I can't use this: since that only works for x=-1 through x=1...

Who knows another summation/computation algorithm? Thanks!
(x-1)/(x+1) +1/3 * [(x-1)/(x+1)]^3 + 1/5 * [(x-1)/(x+1)]^5 + 1/7 * [(x-1)/(x+1)]^7 .....
for x > 0
There are shortcuts on a calculator to do this.

Offline Adriweb

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Re: calculating the natural logarithm of an arbitrary number
« Reply #2 on: December 23, 2011, 12:52:44 pm »
Taylor it :)


(oh, well, bsl actually wrote directly an approximation...)
« Last Edit: December 23, 2011, 12:53:13 pm by adriweb »
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Offline phenomist

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Re: calculating the natural logarithm of an arbitrary number
« Reply #3 on: January 18, 2012, 02:31:34 am »
Also, ln(x)=-ln(1/x)

If x is not between -1 and 1, take its reciprocal. (I'd also like to note that ln(negative number) is a bad idea.)
« Last Edit: January 18, 2012, 02:31:48 am by phenomist »
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