Omnimaga
General Discussion => Other Discussions => Math and Science => Topic started by: Freyaday on April 15, 2011, 04:35:47 pm
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Got some math troubles? Post 'em here and I'll see what I can do.
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Got some math troubles? Post 'em here and I'll see what I can do.
I actually think it'd better if for each trouble we'd create a new topic (as we've been doing so far), but I don't know about what others think.
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This is for little things.
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I think Freyaday is just finding somewhere else to post other than Spam :P
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That too.
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I think Freyaday is just finding somewhere else to post other than Spam :P
I just hope this doens't end like Ashbad's OOP Help topic where nobody eventually asked for help.
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Explain why an + bn = cn where a, b, c, and n ∈ ℤ implies n ≤ 2.
Any simple explanations for that?
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Well, It'd help if you'd spell out the symbol you're using, because then I'd know what's being talked about.
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∈ is set membership, ℤ is set of all integers.
Basically, explain Fermat's last theorem in one post ;D
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I thought I recognized that! Also, that's not something simple. Next!
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Never said it had to be simple :P
Oh well. Still nobody's given me a decent explanation yet.
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Well, I just proved cogito ergo sum, so give me a bit.
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Give me an F(x) style solution to [a]*=[c] where c is a known integer, but neither a nor b are known.
by f(x) I mean
f(x) = x*sin(x)+5
edit: lol at the bbcodes :P
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[nocode][nocode]a=c/b[/nocode][/nocode]
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you forgot the [] brackets mean int()
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[] is not the notation for the floor function. They're just brackets.
|_b_|/c=|_a_|<=a<=|-a-|
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Square brackets are the de-facto way of typing floor functions, IIRC, because I don't have a reverse-L key :P
But anyways, solve int(a)*int(b)=a known integer
The hard part is that there is no inverse int( function :P
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(int(b)=1 and int(a)=a) or a=0
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that's not all solutions though......:(
And a=0 doesn't work, unless c is 0, which it isn't :P
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It is for
int(b)int(a)=a
which is what you posted, innit?
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no, int(b)int(a)=c.
Oh, I see, by "a known integer" I meant int(c) but that you know c :P sorry.
Here's a hex number to start you off. It's easy because there's only 2 sets of results!
0xc3b3a7015c04299ff3a25f104e2285c1ec2d55471e6208959d0f6981b2fa2c6d3e316f9364d5eb5c7789e142b75bfaf402e7e02fac0cb09f6419db1f44679f8bbcca142f1d312feb095708ef175a4ef80271321e7240f0d854c90a74fc59209cdf80aa8f85ae3b948a3ce55c69cd050098d5a79aebbc241cc642b106b1af2cb7
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If you want to get rid of the floors, that'll involve inequalities, which I don't think you're looking for. If you don't mind having floors, then it's {int(a)=c/int(b) c|int(b)