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99binomcdf(127,0->L1augment(L1,L1augment(Ans,L1->L10

I was playing around with some of the other variables.A matrix (32*3) is exactly 875 bytes.Now, is there a way to store complex numbers to said matrix?

Quote from: ProphetsDementia on November 27, 2009, 09:41:21 pmI was playing around with some of the other variables.A matrix (32*3) is exactly 875 bytes.Now, is there a way to store complex numbers to said matrix?I don't think it is possible. Also multiply an entire matrix by a number doesn't work too. This gives an error.

I have a list of exactly 384 elements. Said list is ~3900 bytes.Compressed into complex numbers is ~1950 bytes.

To get said 384 element list:Code: [Select]99binomcdf(127,0->L1augment(L1,L1augment(Ans,L1->L10

:384→dim(L1:Fill(99,L1

I remember multiplying by a number worked. I don't think adding by a number did though.

To add a number to a matrix, you need to create another matrix of the same size, fill it with the number you want to add/subtract, and then you can add/subtract those matrixes. I use this in Shift, ans so i had a dedicated addition matrix

If you store your list as a string to one of the sequence variables, u, v, w, you can half the size of the entire thing.Then, if you need to evaluate it, run 'u' and Ans(X where X is the list element.The only issue with this is the lack of editability if that's a word.