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Author Topic: Random Number question  (Read 7396 times)

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Offline AngelFish

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Re: Random Number question
« Reply #15 on: March 17, 2011, 04:19:49 am »
Well, actually N provides the upper bound for the random number because everything is (mod N) ;)
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∂²Ψ    -(2m(V(x)-E)Ψ
---  = -------------
∂x²        ℏ²Ψ

Offline Xeda112358

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Re: Random Number question
« Reply #16 on: March 17, 2011, 04:23:18 am »
Yeah, sorry :D Actually, I just realised I typed up the wrong equation...

What I meant to say is that I multiply rand by floor(rand/N2) and then take mod N of that result.

I don't know why I said N2 provided an upper bound ...
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Offline AngelFish

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Re: Random Number question
« Reply #17 on: March 17, 2011, 04:27:15 am »
I think you should change it to be n^2. That way your users can scratch their heads trying to figure out how to get Rand mod 2 with integers...
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∂²Ψ    -(2m(V(x)-E)Ψ
---  = -------------
∂x²        ℏ²Ψ
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