Sorry, couldn't help bringing this up:

Mathprint is responsible for more RAM crashes on my calculator than all of my programs combined. Bloody TI...

Oh... I've been wondering how to do that for a little while now. I think if you put an invalid character into the file name, TI-OS shouldn't be able to open it. But my guess is as good as yours.

1. Can axe read from programs stored in the archive? (Then I mean, my program, since my gfx are in a program in the archive)
2. I have this program data file (created the same way as an appvar), but its source is open (I can read it using TIOS's edit), how can I lock this?
3. Can I "break" loops? For example, I have a for loop that goes from 1 to 10, but as soon as it discovers that number 6 is empty, that it will skip the 7-10 as well?

1) If you mean can Axe compile from Archive, then yes. To read data from Archive within a program is possible, I think, but the routines aren't the same as reading from RAM.

2) If you don't want to user to see the source, then I simply wouldn't include the source with the program.

3) You could also use a Goto to skip somewhere in the program. But the 11-->A thing is more memory efficient.

Hey nice sprite editor you posted there. I assume it does all levels of grayscale?

Yep. The last few seconds of the screenie show the implemented greyscale. I'd post another that shows what you can do with the greyscale, but Wabbitemu doesn't seem to be perfectly emulating the program and some of the buttons aren't working, although they do on the actual calculator.

No matter where you store your data in the RAM, it'll be listed in the VAT (variable allocation table). Most experienced calculators users can see the contents of the VAT through a program such as Calcsys. Do I have that right?

That has nothing to do with the derivative, though. I think you're getting derivatives and limits mixed up

That is always a probability.

And the abs(x) example caused me to see the error.

[ Differentiability implies continuity, but continuity does not imply differentiability.

Actually, continuity does imply differentiability. Let's define a function f(x) as continuous on some interval [a, b] if Lim_x->c⁺f(x) = Lim_x->c^-f(x) =f(c) ∀ {c|a≤c≤b} This suggests that a change in c results in a finite change in f(c), which implies that the function has a finite rate of change for all points in the range [a, b]. Thus the derivative exists for the continuous function. It's not a mathematically rigorous proof, but you get the idea.

Note: I might actually know what I'm talking about or be completely wrong. I have no idea which one is right. Feel free to correct me.

Pascal [who does't know it]

*Raises hand*