Author Topic: Changing bits  (Read 3240 times)

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Offline Camdenmil

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Changing bits
« on: January 15, 2011, 07:25:04 pm »
I'm probably missing something, but is there a way to get/set the value of a single bit in axe?
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Offline squidgetx

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Re: Changing bits
« Reply #1 on: January 15, 2011, 07:27:47 pm »
Documentation has this for reading bits:
Code: [Select]
EXPeBIT# where e is euler's e. Returns BIT# of EXP, where the high bit is bit0 and the low bit is bit 7. Example, 255e0 would return 1.

Writing to bits, you basically have to "or" the bit over; so
Code: [Select]
e^(bit#) or EXP -> EXP As for resetting bits, I forget...

edit: here's a more optimizedish version by runer112; http://ourl.ca/7815/138430
« Last Edit: January 15, 2011, 07:28:48 pm by squidgetx »

Offline nemo

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Re: Changing bits
« Reply #2 on: January 15, 2011, 10:04:21 pm »
or will set a bit
and will reset a bit
xor will toggle a bit
Code: [Select]
e^(#) [or/and/xor] EXP->EXP
where # is the bit to set 0-7 starting from the right hand side.


Offline calc84maniac

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Re: Changing bits
« Reply #3 on: January 15, 2011, 10:15:24 pm »
Actually, for and you need to use not(e^(#)) and EXP->EXP
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Offline Binder News

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Re: Changing bits
« Reply #4 on: January 15, 2011, 10:37:55 pm »
How 'bout an Axiom, anyone?
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Offline AngelFish

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Re: Changing bits
« Reply #5 on: January 15, 2011, 10:38:48 pm »
Perhaps I'm behind in my Axe, but I wasn't aware that the Not( function was implemented in Axe.
∂²Ψ    -(2m(V(x)-E)Ψ
---  = -------------
∂x²        ℏ²Ψ

Offline calc84maniac

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Re: Changing bits
« Reply #6 on: January 15, 2011, 10:44:21 pm »
Perhaps I'm behind in my Axe, but I wasn't aware that the Not( function was implemented in Axe.
It was added in Axe 0.4.7: "Bitwise complement command for 8 and 16 bit numbers"
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Offline AngelFish

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Re: Changing bits
« Reply #7 on: January 15, 2011, 10:49:12 pm »
I've been wanting that function for quite some time. Thanks for pointing it out  :)
∂²Ψ    -(2m(V(x)-E)Ψ
---  = -------------
∂x²        ℏ²Ψ