### Author Topic: A little problem  (Read 2372 times)

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#### AngelFish

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##### A little problem
« on: August 06, 2011, 01:36:42 am »
Here's a little ditty related to some stuff I've been working on. This problem has managed to crash Mathematica, confuse Matlab, destroy my attempts at a symbolic solution, and cause Wolfram Alpha to throw a temper tantrum. In short, it's a nasty little bugger and I was wondering if anyone else wanted to take a crack at it:

LimN→∞ N/(2^⌊Log2N⌋)

+10 Math points to anyone who can either solve it or demonstrate that there's no elementary solution
« Last Edit: August 06, 2011, 01:38:44 am by Qwerty.55 »
∂²Ψ    -(2m(V(x)-E)Ψ
---  = -------------
∂x²        ℏ²Ψ

#### phenomist

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##### Re: A little problem
« Reply #1 on: August 06, 2011, 04:06:28 am »
No limit kind sir.

Consider N = 2^k, for arbitrarily large k. then the answer is 1.

Now consider N = 2^k-epsilon, for arbitrarily large k. then the limit is 2.

[note: k = integer]

undefined limit.

(note: have floors, abuse boundary conditions )
« Last Edit: August 06, 2011, 04:08:06 am by phenomist »
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#### AngelFish

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##### Re: A little problem
« Reply #2 on: August 06, 2011, 05:15:20 am »
I suppose that should have been pretty obvious

Thanks.
* Qwerty.55 hands over the promised +10 points
∂²Ψ    -(2m(V(x)-E)Ψ
---  = -------------
∂x²        ℏ²Ψ