I believe it is correct, though I did not look at the code

(If it isn't then a month from now I will make mention of it )

Nope, that's not it . The decimal part is in base 10, not base phi^2 (and happens to be the "ones" place)

Yep, sorry, just caught that. Sorry, lack of sleep
I get:
(sqrt(5)+3)/2=phi^2→D
10/D^2=1.458980338...
First digit=1
.458980338*D=1.201626124
Second digit=1
Decimal=.201626124....*D=.527864045
10 % phi^2=
11.527864045
phi^4+ph^2+.527864045...=10
So the 5th digit after the decimal is 6

EDIT: I forgot the /2 part of the (sqrt(5)+3)/2
EDIT: There is a mistake if anybody can catch it...

Okee, here is some food for thought.
(7x-2) mod 9=0 when x=9K-1
K is an integer
This means that all number that can be expressed as 7(9k-1)-2 can always be divided evenly by 9. This isn't really complex, but it is fun if you like prime numbers

So, when:
x=9k-1     (7x-2) mod 9=0     (7x+7) mod 9=0
x=9k-2     (7x-4) mod 9=0     (7x+5) mod 9=0
x=9k-3     (7x-6) mod 9=0     (7x+3) mod 9=0
x=9k-4     (7x-8) mod 9=0     (7x+1) mod 9=0
x=9k-5     (7x-1) mod 9=0     (7x+8) mod 9=0
x=9k-6     (7x-3) mod 9=0     (7x+6) mod 9=0
x=9k-7     (7x-5) mod 9=0     (7x+4) mod 9=0
x=9k-8     (7x-7) mod 9=0     (7x+2) mod 9=0

When I did this, I learned some things about how numbers work. If you wanna have fun, try using values other than 7 and 9. Something this simple can reveal quite a bit about numbers.

Okee, as a mini trick say you have X^2+2X+1 and you want to find the square root of it. Replace the X's with 10's and you get 121. Find the square root of that and you get 11. 11 is 10+1, so replace the 10 with X and you get x+1.

Here is what is really going on:
121=1*10^2+2*10^1+1
X^2+2x+1 is the same thing if X=10.
So really you are only changing the base of the number

So if you want to find the square root of x^2+8X+16, you get 100+80+16=196. sqrt(196)=14=(X+4). Now what if you wanted to find the square root of 169? If you are bored, you can do:
169=10^2+6*10+9=x^2+6x+9

0=x^2+6x+9
-9=x^2+6x
9-9=(x+3)^2
0=(X+3)^2
0=X+3
10+3=13 is the square root

So what happens if I do 187...?
0=x^2+8x+7
-7=X^2+8x
16-7=(X+4)^2
9=(X+4)^2
STOP
x+4=14
187 is 9 away from 14^2

As a note, the second digit has to be even, so if you have 196, take 1 from the 9 and add 10 to the 6

Also, if I had a copy of my notes, I would show y'all what I am calling the "optimal base" for numbers. For numbers like 225, you need to do 100+100+25, not 100+120+5. The optimal base is a special number base where every number is a three digit number with the first being 1. There is an equation for it ( have it in an excel spreadsheet) and 196 is the only number that fails. Interestingly, if you check the number 196 on Wolfram.com, you will find that 196 is a very interesting number and has some unique properties that might tied into this.

Oh jeez, one letter difference...

Anywho, on another coincidental note, it was only a few weeks after I started going by the name of Zeda that I learned about the Riemann Zeta function... So that is nice

I had to use a debugger to figure out what exactly goes on in a fonthook, then I just used my own drawing routine for fonts. For the 8x8 font, the last 4 chars in each line are not drawn. I am not sure why my fonthooks seem to fail in menu's, though. Here are some more random screen shots if ya be interested... Arrrrr